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Question 22 of 37

Q.The derivative of f(x)=axf(x) = a^x, where a is constant is x⋅ax−1x \cdot a^{x-1}.

(a) True
(b) False
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023MCQ· 1mImportance★★★★★
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The claimed derivative uses the power rule wrongly; the true derivative of axa^x is axlog⁡aa^x \log a, so the statement is False.

The statement claims ddx(ax)=x⋅ax−1\dfrac{d}{dx}(a^x) = x \cdot a^{x-1}. This is the form of the power rule ddx(xn)=nxn−1\dfrac{d}{dx}(x^n) = n x^{n-1}, where the base is the variable and the exponent is constant.

But in axa^x the base aa is a constant and the exponent xx is the variable — this is an exponential function, not a power function. Its correct derivative is: …

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