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Worked Examples · Example 12

Q.A loan of ₹50,000 is to be repaid in 3 equal annual instalments at 10% per annum. Find the annual instalment (EMI). [Given (1.1)^3 = 1.331]

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The loan principal P=₹50,000P=₹50{,}000 equals the present value of the three instalments, so use the EMI formula with i=0.10i=0.10, n=3n=3:

EMI=P[i(1+i)n(1+i)n−1]=50000[0.1×(1.1)3(1.1)3−1]=50000[0.1×1.3311.331−1]=50000×0.13310.331.\text{EMI}=P\left[\frac{i(1+i)^{n}}{(1+i)^{n}-1}\right]=50000\left[\frac{0.1\times(1.1)^{3}}{(1.1)^{3}-1}\right]=50000\left[\frac{0.1\times1.331}{1.331-1}\right]=50000\times\frac{0.1331}{0.331}.

So

EMI=66550.331≈₹20,105.74.\text{EMI}=\frac{6655}{0.331}\approx ₹20{,}105.74. …

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