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Worked Examples · Example 7

Q.A person deposits ₹2,000 at the end of each year for 3 years into an account paying 10% per annum compounded annually. Find the accumulated value of this annuity. [Given (1.1)^3 = 1.331]

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Payments are made at the end of each year, so this is an immediate (ordinary) annuity with C=2000C=2000, i=0.10i=0.10, n=3n=3:

A=C[(1+i)n−1i]=2000[(1.1)3−10.1]=2000[1.331−10.1]=2000×0.3310.1=2000×3.31=₹6,620.A=C\left[\frac{(1+i)^{n}-1}{i}\right]=2000\left[\frac{(1.1)^{3}-1}{0.1}\right]=2000\left[\frac{1.331-1}{0.1}\right]=2000\times\frac{0.331}{0.1}=2000\times3.31=₹6{,}620.

Check (independent verification) — grow each deposit separately:

  • End of year 1 deposit earns interest for 2 years: 2000×(1.1)2=2000×1.21=₹2,4202000\times(1.1)^{2}=2000\times1.21=₹2{,}420. …

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