Skip to content
Select the most correct choice · Q1

Q.CH2OH-CO-(CHOH)4-CH2OH is an example of
a. Aldohexose
b. Aldoheptose
c. Ketotetrose
d. Ketoheptose

Maharashtra MsbshseTextbookMCQImportance★★★★★
20% · 15/74 Questions
✓ Free question

Step 1. Count the carbon atoms in CH2OH-CO-(CHOH)4-CH2OH: CH2OH (1 carbon) + CO (1 carbon) + (CHOH)4 (4 carbons) + CH2OH (1 carbon) = 7 carbons total.

Step 2. Identify the carbonyl type: the carbonyl carbon here is written as -CO-, i.e. flanked by carbon on both sides (not a terminal -CHO), so it is a KETONE, not an aldehyde -- this makes the compound a ketose, not an aldose.

Step 3. Combine: 7 carbons + ketone = ketoheptose (by the same naming convention that makes 6-carbon glucose an aldohexose and 6-carbon fructose a ketohexose, section 14.2.2).

✓Final answer

d. Ketoheptose

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.