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Question 95 of 100

Q.Solve the L.P.P. by graphical method, Minimize z=8x+10yz = 8x + 10y Subject to 2x+y≥72x+y \ge 7, 2x+3y≥152x+3y \ge 15, y≥2y \ge 2, x≥0x \ge 0

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2022Subjective· 4mImportance★★★★★
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Find the feasible region's corner points (region is unbounded above) and evaluate zz there.

Constraints: 2x+y≥72x+y\ge7, 2x+3y≥152x+3y\ge15, y≥2y\ge2, x≥0x\ge0.

Corner points of the feasible region:

  • Intersection of 2x+y=72x+y=7 and 2x+3y=152x+3y=15: subtracting, 2y=8⇒y=42y=8\Rightarrow y=4, then 2x+4=7⇒x=1.52x+4=7\Rightarrow x=1.5. Point (1.5,4)(1.5,4).
  • Intersection of 2x+3y=152x+3y=15 and y=2y=2: 2x+6=15⇒x=4.52x+6=15\Rightarrow x=4.5. Point (4.5,2)(4.5,2) — check 2(4.5)+2=11≥72(4.5)+2=11\ge7 ✓.
  • Intersection of 2x+y=72x+y=7 and x=0x=0: (0,7)(0,7) — check 2(0)+3(7)=21≥152(0)+3(7)=21\ge15 ✓.

(The point where 2x+y=72x+y=7 meets y=2y=2, i.e. (2.5,2)(2.5,2), fails 2x+3y≥152x+3y\ge15 since 11<1511<15, so it is not a vertex of the feasible region.)

The feasible region is unbounded (extends outward/upward), with vertices (0,7)(0,7), (1.5,4)(1.5,4), (4.5,2)(4.5,2).

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