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Exercise 2.1 · Q2

Q.Apply the given elementary transformation on the following matrix. B=[1−13254]B = \begin{bmatrix} 1 & -1 & 3 \\ 2 & 5 & 4 \end{bmatrix}, R1→R1−R2R_1 \rightarrow R_1 - R_2.

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Step 1: B=[1−13254]B = \begin{bmatrix} 1 & -1 & 3 \\ 2 & 5 & 4 \end{bmatrix}.

Step 2: R1→R1−R2R_1 \to R_1 - R_2 means every entry of the new row 1 is (old row 1 entry) −- (old row 2 entry), column by column; row 2 itself is left unchanged, as transformation (c) requires.

Step 3: New R1=(1−2, −1−5, 3−4)=(−1,−6,−1)R_1 = (1-2,\ -1-5,\ 3-4) = (-1,-6,-1).

✓Final answer

B∼[−1−6−1254]B \sim \begin{bmatrix} -1 & -6 & -1 \\ 2 & 5 & 4 \end{bmatrix}

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