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Exercise 2.1 · Q8

Q.Convert [1−123]\begin{bmatrix} 1 & -1 \\ 2 & 3 \end{bmatrix} into an identity matrix by suitable row transformations.

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Step 1: A=[1−123]A=\begin{bmatrix}1&-1\\2&3\end{bmatrix}. Use R2→R2−2R1R_2\to R_2-2R_1 to clear the (2,1) entry: new row 2 =(2−2(1), 3−2(−1))=(0,5)=(2-2(1),\ 3-2(-1))=(0,5), giving A∼[1−105]A\sim\begin{bmatrix}1&-1\\0&5\end{bmatrix}.

Step 2: Use R2→15R2R_2\to \tfrac15R_2 to make the (2,2) entry equal to 11: A∼[1−101]A\sim\begin{bmatrix}1&-1\\0&1\end{bmatrix}. …

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