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Question 118 of 121

Q.Find the adjoint of the matrix [2−243]\begin{bmatrix}2 & -2\\ 4 & 3\end{bmatrix}.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 2mImportance★★★★★
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For a 2×22\times2 matrix A=[abcd]A=\begin{bmatrix}a&b\\c&d\end{bmatrix}, adj(A)=[d−b−ca]\text{adj}(A)=\begin{bmatrix}d&-b\\-c&a\end{bmatrix}.

Given A=[2−243]A=\begin{bmatrix}2 & -2\\ 4 & 3\end{bmatrix}, so a=2, b=−2, c=4, d=3a=2,\ b=-2,\ c=4,\ d=3.

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