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Miscellaneous Exercise · Q23

Q.Find the derivative of (x2+1)cos⁡x(x^2 + 1)\cos x.

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We differentiate the product (x2+1)cos⁡x(x^2+1)\cos x using the Product Rule, not the Quotient Rule. The derivative is 2xcos⁡x−(x2+1)sin⁡x2x\cos x - (x^2+1)\sin x.

This is a product of two functions — x2+1x^2+1 and cos⁡x\cos x — so the Product Rule is the natural tool. The Product Rule says: if y=u⋅vy = u \cdot v, then

dydx=u′v+uv′\frac{dy}{dx} = u'v + uv'.

We differentiate each piece separately, then combine.

  1. Identify the two factors

    Let u=x2+1u = x^2 + 1 and v=cos⁡xv = \cos x.

  2. Differentiate each

    • u′=ddx(x2+1)=2xu' = \frac{d}{dx}(x^2 + 1) = 2x
    • v′=ddx(cos⁡x)=−sin⁡xv' = \frac{d}{dx}(\cos x) = -\sin x
  3. Apply the Product Rule

dydx=u′v+uv′=(2x)(cos⁡x)+(x2+1)(−sin⁡x)\frac{dy}{dx} = u'v + uv' = (2x)(\cos x) + (x^2 + 1)(-\sin x)

  1. Simplify dydx=2xcos⁡x−(x2+1)sin⁡x\frac{dy}{dx} = 2x\cos x - (x^2 + 1)\sin x …

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