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Miscellaneous Exercise · Q6

Q.Find the derivative of 1+1x1−1x\dfrac{1 + \frac{1}{x}}{1 - \frac{1}{x}}.

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Simplify the compound fraction to x+1x−1\dfrac{x+1}{x-1}, then apply the Quotient Rule. The derivative is −2(x−1)2\dfrac{-2}{(x-1)^2}.

Simplify first

Multiply numerator and denominator by xx:

1+1x1−1x=x(1+1x)x(1−1x)=x+1x−1\frac{1+\frac{1}{x}}{1-\frac{1}{x}} = \frac{x\left(1+\frac{1}{x}\right)}{x\left(1-\frac{1}{x}\right)} = \frac{x+1}{x-1}

Differentiate

Let y=x+1x−1y=\dfrac{x+1}{x-1} with u=x+1, v=x−1u=x+1,\ v=x-1.

Step 1 — Quotient rule.

dydx=v u′−u v′v2\frac{dy}{dx}=\frac{v\,u'-u\,v'}{v^2}

Step 2 — Component derivatives. u′=1,v′=1u'=1,\quad v'=1.

Step 3 — Substitute.

dydx=(x−1)(1)−(x+1)(1)(x−1)2\frac{dy}{dx}=\frac{(x-1)(1)-(x+1)(1)}{(x-1)^2} …

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