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Q.If the function f:R→Rf : R \to R is defined by
[!FORMULA] f(x)={2x+3,if x<−2x2−2,if −2≤x≤33x−1,if x>3f(x) = \begin{cases} 2x+3, & \text{if } x < -2 \\ x^2-2, & \text{if } -2 \le x \le 3 \\ 3x-1, & \text{if } x > 3 \end{cases}
find f(2),f(4),f(−1)f(2), f(4), f(-1) and f(−3)f(-3).

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2021Subjective· 2mImportance★★★★★
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Matching each input to the correct branch of the piecewise rule and substituting gives f(2)=2f(2)=2, f(4)=11f(4)=11, f(−1)=−1f(-1)=-1, f(−3)=−3f(-3)=-3.

The function is

f(x)={2x+3,x<−2x2−2,−2≤x≤33x−1,x>3f(x)=\begin{cases}2x+3,& x<-2\\ x^2-2,& -2\le x\le3\\ 3x-1,& x>3\end{cases}

f(2)f(2): since −2≤2≤3-2\le2\le3, use x2−2x^2-2: f(2)=22−2=4−2=2f(2)=2^2-2=4-2=2.

f(4)f(4): since 4>34>3, use 3x−13x-1: f(4)=3(4)−1=12−1=11f(4)=3(4)-1=12-1=11.

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