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Q.State the range of the signum function.

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2022Subjective· 1mImportance★★★★★
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The signum function f(x)=∣x∣xf(x)=\dfrac{|x|}{x} for x≠0x\neq0 and f(0)=0f(0)=0 takes only three possible values, so its range is {−1,0,1}\{-1,0,1\}.

The signum function is defined as

f(x)={1,x>00,x=0−1,x<0f(x)=\begin{cases}1, & x>0\\0, & x=0\\-1, & x<0\end{cases}

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