Q.(a) Define isothermal change. Calculate the amount of work done when a perfect gas expands isothermally.

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1. CBSE 2026Set ANNUAL1 markMCQ
   Q.A system releases 10 kJ of heat and performs 15 kJ of work on the surrounding. Hence the change in internal energy is:

   (a) +5 kJ

   (b) –5 kJ

   (c) +25 kJ

   (d) –25 kJ

   ›Reveal solutionSolution

   $\Delta U = q + w = (-10) + (-15) = -25$ kJ.

   By the first law of thermodynamics, $\Delta U = q + w$, where $q$ is heat absorbed by the system and $w$ is work done on the system.

   The system releases 10 kJ of heat, so $q = -10$ kJ (heat lost by the system).

   …

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2. CBSE 2026Set ANNUAL1 markMCQ
   Q.In an isothermal process, the internal energy of an ideal gas:

   (a) Decreases

   (b) Increases

   (c) Remains constant

   (d) First increases, then decreases

   ›Reveal solutionSolution

   For an ideal gas, $U$ is a function of $T$ alone, so a constant-temperature (isothermal) process leaves $U$ unchanged.

   For an ideal gas, the internal energy $U$ arises purely from the kinetic energy of its molecules, which depends only on the absolute temperature $T$ (there are no intermolecular potential energy terms in the ideal-gas model). Formally, $U=nC_vT$ (plus a constant), so $U$ is a function of temperature alone.

   …

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3. CBSE 2026Set ANNUAL1 markMCQ
   Q.Two statements are given below, one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes below. Assertion (A): Work and heat are two equivalent form of energy. Reason (R): Work is the transfer of mechanical energy irrespective of temperature difference, whereas heat is the transfer of thermal energy because of temp. difference only.

   (a) Both (A) and (R) are true and (R) is the correct explanation of (A).

   (b) Both (A) and (R) are true, but (R) is not the correct explanation of (A).

   (c) (A) is true, but (R) is false.

   (d) (A) and (R) both are false.

   ›Reveal solutionSolution

   Both statements are individually correct, but R describes how work and heat differ, not why they're equivalent energy forms — that equivalence instead comes from the first law of thermodynamics.

   Assertion (A): Work and heat are both genuinely modes of energy transfer, measured in the same SI unit (joule), and this equivalence (Joule's mechanical-equivalent-of-heat result) underlies the first law of thermodynamics, $\Delta U = Q - W$. So A is true.

   Reason (R): It correctly defines the two: work is the transfer of (mechanical) energy that doesn't require a temperature difference, while heat is energy transferred specifically because of a temperature difference. This is also a true statement.

   …

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4. CBSE 2026Set ANNUAL1 markMCQ
   Q.First law of Thermodynamics is the law of Conservation of :

   (a) Mass

   (b) Energy

   (c) Linear Momentum

   (d) Angular Momentum.

   ›Reveal solutionSolution

   The First Law of Thermodynamics is the law of conservation of energy applied to heat and work.

   The First Law of Thermodynamics is stated as:

   ΔQ = ΔU + ΔW

   where ΔQ is the heat supplied to the system, ΔU is the change in internal energy, and ΔW is the work done by the system.

   …

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5. CBSE 2026Set sz1 markMCQ
   Q.In a cyclic process:

   (a) the net work done is always positive

   (b) the change in internal energy is zero

   (c) the net heat transfer is zero

   (d) the process is always reversible

   ›Reveal solutionSolution

   In any cyclic process, the internal energy returns to its starting value, so delta U (over the whole cycle) = 0.

   Internal energy U is a state function — it depends only on the state (e.g. temperature, for an ideal gas) of the system, not on the path taken to reach that state. In a cyclic process the system is brought back to exactly its initial state after one complete cycle, so U_final = U_initial, giving delta U = 0 for the cycle. This does not mean the net work done or net heat transferred is zero — from the first law, delta Q = delta U …

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6. CBSE 2025Set ANNUAL1 markMCQ
   Q.The first law of thermodynamics is a statement of (A) law of conservation of momentum (B) law of conservation of energy (C) law of conservation of angular momentum (D) None of these

   ›Reveal solutionSolution

   The first law of thermodynamics is simply the law of conservation of energy applied to thermal systems.

   The first law states: $dQ = dU + dW$, i.e. heat supplied to a system either increases its internal energy or is used to do external work (or both). This is a generalization of the mechanical law of conservation of energy to include heat as a fo …

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7. CBSE 2025Set ANNUAL1 markMCQ
   Q.A system goes from state i to state f through a process in which internal energy increases by 20 joule. If only the process be replaced by another, the increase in internal energy will be (A) the same (B) less than 20 joule (C) more than 20 joule (D) none of these

   ›Reveal solutionSolution

   Internal energy change between the same two states is always the same, regardless of the process (path) used.

   Internal energy $U$ is a state function — it depends only on the state (pressure, volume, temperature) of the system, not on the history or path by which that state was reached. This is a direct consequence of the first law of thermodynamics.

   …

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8. CBSE 2025Set ANNUAL1 markMCQ
   Q.First law of thermodynamics leads to

   (a) Conservation of mass

   (b) Conservation of linear momentum

   (c) Conservation of energy

   (d) Conservation of angular momentum

   ›Reveal solutionSolution

   The first law of thermodynamics states that heat supplied to a system equals the increase in internal energy plus the work done by the system, which is precisely a statement of energy conservation for thermal processes.

   The first law is written as:

   dQ = dU + dW

   (heat supplied = change in internal energy + work done by the system)

   …

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9. CBSE 2025Set hz1 markMCQ
   Q.The work done in an isothermal expansion of a gas depends upon:

   (a) Temperature only

   (b) Expansion ratio only

   (c) Both of them

   (d) None of them

   ›Reveal solutionSolution

   For an ideal gas undergoing isothermal expansion, W = nRT ln(V2/V1) -- this formula explicitly contains both the temperature T and the expansion ratio V2/V1, so the work done depends on both.

   For an ideal gas at constant temperature T expanding reversibly from volume V1 to V2, using PV = nRT (so P = nRT/V):

   W = integral from V1 to V2 of P dV = integral from V1 to V2 of (nRT/V) dV = nRT ln(V2/V1)

   This single expression shows two dependencies at once:

   • It is directly proportional to T -- a higher (constant) temperature means more work is done for the same expansion ratio. …

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10. CBSE 2025Set ANNUAL1 markMCQ
    Q.The thermodynamic process in which internal energy remains constant is

    (a) adiabatic

    (b) isothermal

    (c) isochoric

    (d) isobaric

    ›Reveal solutionSolution

    For an ideal gas the internal energy $U$ is a function of temperature alone ($U=nC_vT$).

    In an isothermal process the temperature $T$ is held constant throughout, so $\Delta U=0$, i.e. internal energy remains constant. (Contrast: in an adiabatic process $Q=0$ but $T$, an …

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11. CBSE 2025Set ANNUAL1 markMCQ
    Q.For an adiabatic process, the true statement is -

    (a) ΔQ = ΔU + ΔW

    (b) ΔQ = ΔW

    (c) ΔQ = ΔU

    (d) ΔU + ΔW = 0

    ›Reveal solutionSolution

    For an adiabatic process, ΔQ = 0, so the first law of thermodynamics gives ΔU + ΔW = 0.

    The first law of thermodynamics states: ΔQ = ΔU + ΔW, where ΔQ is heat supplied to the system, ΔU is the change in internal energy, and ΔW is the work done by the system.

    An adiabatic process is, by definition, one in which no heat enters or leaves the system, i.e., ΔQ = 0. …

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12. CBSE 2024Set ANN1 mark
    Q."The heat given to a system is used to increase the internal energy and doing external work". This is

    (a) Zeroth law in thermodynamics

    (b) First law in thermodynamics

    (c) Second law in thermodynamics

    (d) Newton's third law in motion

    ›Reveal solutionSolution

    The statement describes heat splitting into a rise in internal energy plus external work done — this is precisely the First Law of Thermodynamics, a statement of energy conservation.

    The First Law of Thermodynamics says that when an amount of heat ΔQ is given to a system, it can go into two things:

    1. Increasing the internal energy of the system, ΔU
    2. Being used by the system to do external work, ΔW (e.g. a gas expanding and pushing back the surroundings)

    Mathematically:

    ΔQ = ΔU + ΔW

    This is essentially a statement of the law of conservation of energy applied to thermal processes. It is distinct from: …

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