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Q.Predict which of the following will be coloured in aqueous solution: Sc3+Sc^{3+}, Fe3+Fe^{3+}, Ti4+Ti^{4+}, V3+V^{3+} (Atomic nos. of Sc, Fe, Ti and V are 21, 26, 22 and 23 respectively)

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2019Subjective· 1mImportance★★★★★
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Colour in transition-metal ions arises from d–d electronic transitions, which require partly-filled d-orbitals; ions with a d0d^0 configuration have no such transition available and are colourless.

Work out each ion's d-electron count:

  • Sc3+Sc^{3+} (Z = 21): Sc is [Ar]3d14s2[Ar]3d^1 4s^2; removing 3 electrons (4s24s^2, 3d13d^1) gives Sc3+=[Ar]3d0Sc^{3+} = [Ar]3d^0 — no d electrons.
  • Ti4+Ti^{4+} (Z = 22): Ti is [Ar]3d24s2[Ar]3d^2 4s^2; removing all 4 gives Ti4+=[Ar]3d0Ti^{4+} = [Ar]3d^0 — no d electrons.
  • Fe3+Fe^{3+} (Z = 26): Fe is [Ar]3d64s2[Ar]3d^6 4s^2; removing 3 electrons (4s24s^2, one 3d3d) gives Fe3+=[Ar]3d5Fe^{3+} = [Ar]3d^5 — 5 unpaired d electrons.
  • V3+V^{3+} (Z = 23): V is [Ar]3d34s2[Ar]3d^3 4s^2; removing 3 electrons (4s24s^2, one 3d3d) gives V3+=[Ar]3d2V^{3+} = [Ar]3d^2 — 2 unpaired d electrons. …

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