Q.a. i) State the first law of thermodynamics.
OF2(g) + H2O(g) -> O2(g) + 2HF(g) at 298K.
Given, standard enthalpies of formation in KJ mol-1 are
OF2(g) = +20, H2O(g) = -250 and HF(g) = -270. OR b. i) Define Gibbs energy and enthalpy.
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Start your 14-day free trial to unlock the full solution →First law: ΔU = q + w. ΔH = ΔU + ΔngRT. For the given reaction, ΔrH° = −310 kJ/mol and ΔU° ≈ −312.5 kJ/mol.
i) First law of thermodynamics: Energy can neither be created nor destroyed, only converted from one form to another; the total energy of an isolated system remains constant. For a system, the change in internal energy equals the heat supplied to the system plus the work done on the system: .
ii) Relationship between ΔH and ΔU: Enthalpy is defined as . At constant pressure, for a finite change: . For a reaction involving ideal gases at constant T and P, (where = moles of gaseous products − moles of gaseous reactants), giving:
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