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Q.Complete the following reaction:

i) CH3MgCl + CO2 --(ether)--> ? --(H3O+)--> ?
ii) 2 CH3-CHO --(dil. NaOH, Δ)--> ?
iv) CH3-CH=CH-COCl --(H2, Pd-BaSO4)--> ?
Nagaland NbseNagaland Board of School Education 2025Subjective· 3mImportance★★★★★
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Grignard + CO2 builds a carboxylic acid one carbon longer; base-catalyzed self-aldol of acetaldehyde condenses to crotonaldehyde; and a poisoned-Pd (Rosenmund) hydrogenation stops an acid chloride's reduction cleanly at the aldehyde.

(i) A Grignard reagent adds to the electrophilic carbon of CO₂ exactly as it would to any carbonyl, giving (after hydrolysis) a carboxylic acid one carbon longer than the original halide: CH₃MgCl + CO₂ --(dry ether)--> CH₃COOMgCl (magnesium salt) --(H₃O⁺)--> CH₃COOH (acetic acid).

(ii) Acetaldehyde has α-hydrogens, so dilute base (NaOH) generates its enolate, which attacks the carbonyl carbon of a second acetaldehyde molecule (aldol addition) to give 3-hydroxybutanal; heating (Δ) then dehydrates this β-hydroxy-aldehyde (aldol condensation) to the conjugated enal: 2CH₃CHO --(dil. NaOH)--> CH₃CH(OH)CH₂CHO --(Δ, −H₂O)--> CH₃–CH=CH–CHO (crotonaldehyde, but-2-enal).

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