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Q.Derive an expression for the resistivity of a conductor in terms of number density of free electrons and relaxation time.

Nagaland NbseNagaland Board of School Education 2019Subjective· 2mImportance★★★★★
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From the drift-velocity picture of conduction, ρ=m/(ne2τ)\rho=m/(ne^2\tau).

Consider a conductor of free-electron number density nn (electrons per unit volume), with each electron of charge −e-e and mass mm, subjected to an electric field EE. Between collisions (average relaxation time τ\tau), an electron acquires drift velocity

vd=eEτmv_d = \dfrac{eE\tau}{m}

(the acceleration a=eE/ma=eE/m acting for average time τ\tau).

The current density (current per unit cross-sectional area) due to nn electrons per unit volume, each carrying charge ee and moving with drift speed vdv_d, is

J=nevd=ne(eEτm)=ne2τmEJ = nev_d = ne\left(\dfrac{eE\tau}{m}\right) = \dfrac{ne^2\tau}{m}E

Comparing with the microscopic form of Ohm's law, J=σEJ=\sigma E, where σ\sigma is the conductivity:

σ=ne2τm\sigma = \dfrac{ne^2\tau}{m}

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