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Worked Examples · Example 8.17

Q.Write resonance structures of CH₂=CH–CHO. Indicate relative stability of the contributing structures.

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Shifting the π electrons of the conjugated C=C–C=O system of CH₂=CH–CHO gives three contributing structures: the neutral molecule (I), a charge-separated form with the negative charge on oxygen (II), and a reversed form with a positive oxygen and negative carbon (III). Stability: I > II > III, with III contributing essentially nothing.

Acrolein, CH₂=CH–CHO, has a C=C double bond conjugated with the C=O of the aldehyde group, so its real electron distribution cannot be captured by a single Lewis structure. Curved arrows shift the π electrons across the conjugated system to generate the contributing (canonical) structures; a double-headed arrow (↔\leftrightarrow) connects them.

The three contributing structures

Structure I — the neutral molecule.

CH2=CH−CH=O\text{CH}_2=\text{CH}-\text{CH}=\text{O}

No formal charges; every carbon and the oxygen has a complete octet; the maximum number of covalent bonds.

Structure II — π electrons shifted toward oxygen.

Pushing the C=C π pair toward the carbonyl and the C=O π pair onto oxygen relays electron density down the chain and gives

C+H2−CH=CH−O−\overset{+}{\text{C}}\text{H}_2-\text{CH}=\text{CH}-\overset{-}{\text{O}}

The terminal carbon carries the positive charge (an incomplete octet) and the oxygen the negative charge.

Structure III — the reversed polarisation.

C−H2−CH=CH−O+\overset{-}{\text{C}}\text{H}_2-\text{CH}=\text{CH}-\overset{+}{\text{O}}

Here the charges are exchanged: oxygen becomes positive and carbon negative.

Ranking the structures

The standard stability rules for resonance structures: more covalent bonds > complete octets > minimal charge separation > negative charge on the more electronegative atom.

  1. I is most stable — most covalent bonds, all octets complete, no separation of opposite charges. …

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