Q.Differentiate with respect to using first principle: .
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Start your 14-day free trial to unlock the full solution →To differentiate using the first principle, we apply the limit definition of the derivative. The key is to use algebraic identities like and to simplify the expression before taking the limit, leading to the result .
The first principle of differentiation is a fundamental concept that defines the derivative of a function. It's not just a formula; it's the very definition of what a derivative is. Geometrically, the derivative of a function at a point represents the slope of the tangent line to the curve at that point.
How do we find the slope of a tangent line? We start by approximating it with the slope of a secant line. Consider two points on the curve: and . The slope of the secant line connecting these two points is given by:
As the second point gets infinitesimally close to the first point , meaning approaches , the secant line approaches the tangent line. Thus, the slope of the tangent line (the derivative) is the limit of the secant slopes as .
The derivative of a function with respect to , denoted as , is defined by the first principle as:
Let's apply this definition to differentiate .
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Identify the function:
We are given .
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Determine :
Substitute into the function:
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Set up the limit expression:
Substitute and into the first principle formula:
- Algebraic manipulation to simplify the numerator: This is the crucial step. We need to simplify the expression so that we can evaluate the limit as without encountering an indeterminate form like . Let and . Then the numerator is . We can factor this using the difference of squares identity: . So, the numerator becomes:
Now, substitute this back into the limit expression:
We can rewrite this as a product of two limits (if they both exist):
Let's evaluate the second limit first, as it's straightforward:
Now, we need to deal with the first limit: $\lim_{h \to 0} \frac{(x+h)^{1/3} - x^{1/3}}{h}$.
This is still in the $\frac{0}{0}$ form. To resolve this, we use the difference of cubes identity: $a^3 - b^3 = (a-b)(a^2+ab+b^2)$.
Let $a = (x+h)^{1/3}$ and $b = x^{1/3}$. Then $a-b = (x+h)^{1/3} - x^{1/3}$.
To make the numerator $a^3-b^3$, we multiply the numerator and denominator by $a^2+ab+b^2$:
So, for the first limit term: …
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