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Exercise 14.2 · Q4

Q.A card is selected from a pack of 52 cards.

(a) How many points are there in the sample space?
(b) Calculate the probability that the card is an ace of spades.
(c) Calculate the probability that the card is
(i) an ace
(ii) black card.
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The sample space has 52 equally likely outcomes. The probability of drawing the ace of spades is 152\frac{1}{52}; of any ace is 113\frac{1}{13}; of a black card is 12\frac{1}{2}.

Classical probability works here because every card in a well-shuffled pack has the same chance of being selected. The sample space is simply the set of all possible outcomes — in this case, all 52 distinct cards. No card is favoured over another, so we can count favourable outcomes and divide by the total number of equally likely outcomes.

Let’s go through each part.

  1. Sample space size

    A standard pack has 52 cards, each unique by suit and rank. So the number of points in the sample space is 5252.

  2. Probability of the ace of spades

    There is exactly one ace of spades in the pack.

P(ace of spades)=number of favourable outcomestotal outcomes=152P(\text{ace of spades}) = \frac{\text{number of favourable outcomes}}{\text{total outcomes}} = \frac{1}{52}

  1. Probability of an ace There are 4 aces in the pack (one per suit).

P(ace)=452=113P(\text{ace}) = \frac{4}{52} = \frac{1}{13}

  1. Probability of a black card Half the cards are black (spades and clubs). That’s 26 cards.

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