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Exercise 1.4 · Q11

Q.If R is the set of real numbers and Q is the set of rational numbers, then what is R – Q?

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The set difference R−QR - Q removes all rational numbers from the real numbers, leaving only the irrational numbers. So R−QR - Q is the set of all irrational numbers.

The question asks: if RR is the set of real numbers and QQ is the set of rational numbers, what is R−QR - Q? This is a set difference problem, and the key is understanding what each set contains and what the minus sign means.

Set difference A−BA - B (also written A∖BA \setminus B) means: take everything in AA, and remove anything that also belongs to BB. So R−QR - Q means: start with all real numbers, then delete every rational number. What remains?

The real numbers RR consist of two disjoint types of numbers: rational numbers (like 22, −3/4-3/4, 0.333…0.333\ldots, 4\sqrt{4}) and irrational numbers (like π\pi, 2\sqrt{2}, ee, 0.1010010001…0.1010010001\ldots). Rational numbers are those that can be written as p/qp/q where pp and qq are integers and q≠0q \neq 0. Irrational numbers are real numbers that are not rational — they cannot be expressed as a ratio of integers.

So when you remove all rationals from the reals, you are left with exactly the irrationals. There is no other category of real numbers.

Watch out

A common mistake is to think R−QR - Q means "real numbers minus rational numbers" in an arithmetic sense, like subtraction. It is set difference, not arithmetic subtraction. You are removing elements, not performing a numerical operation.

Let’s walk through it step by step.

  1. Identify the universal set: RR is the set of all real numbers — every point on the number line, including integers, fractions, decimals that terminate or repeat, and decimals that never repeat.

  2. Identify the subset to remove: QQ is the set of all rational numbers — numbers of the form ab\frac{a}{b} where a,b∈Za, b \in \mathbb{Z} and b≠0b \neq 0. This includes all integers, all finite decimals, and all repeating decimals. …

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