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Exercise 1.4 · Q5

Q.Find the intersection of each pair of sets of question 1 above.

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Using the same five pairs of sets as Question 1 of this exercise, their intersections are: (i) {1,3}\{1,3\},

(ii) {a}\{a\},

(iii) {3}\{3\},

(iv) ∅\emptyset,

(v) ∅\emptyset.

This question reuses the five pairs of sets from Question 1 of the same exercise and asks for the intersection (∩\cap) of each pair -- the elements common to both sets.

(i) X={1,3,5}X=\{1,3,5\}, Y={1,2,3}Y=\{1,2,3\}. The elements appearing in both are 11 and 33.

X∩Y={1,3}X \cap Y = \{1,3\}

(ii) A={a,e,i,o,u}A=\{a,e,i,o,u\}, B={a,b,c}B=\{a,b,c\}. Only aa appears in both.

A∩B={a}A \cap B = \{a\}

(iii) A={x:x is a natural number and a multiple of 3}={3,6,9,12,… }A = \{x : x \text{ is a natural number and a multiple of } 3\} = \{3,6,9,12,\dots\}, B={x:x is a natural number less than 6}={1,2,3,4,5}B = \{x : x \text{ is a natural number less than } 6\} = \{1,2,3,4,5\}. The only multiple of 3 that is also less than 6 is 33.

A∩B={3}A \cap B = \{3\}

(iv) A={x:x is a natural number,1<x≤6}={2,3,4,5,6}A = \{x : x \text{ is a natural number}, 1 < x \le 6\} = \{2,3,4,5,6\}, B={x:x is a natural number,6<x<10}={7,8,9}B = \{x : x \text{ is a natural number}, 6 < x < 10\} = \{7,8,9\}. No number can be both ≤6\le 6 and >6> 6 at once.

A∩B=∅A \cap B = \emptyset …

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