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NCERT Exemplar · Q14

Q.The transverse displacement of a string (clamped at its both ends) is given by y(x,t)=0.06sin⁡(2πx/3)cos⁡(120πt)y(x,t) = 0.06\sin(2\pi x/3)\cos(120\pi t). All the points on the string between two consecutive nodes vibrate with (Note: more than one of the given options may be correct.)

(a) same frequency
(b) same phase
(c) same energy
(d) different amplitude.
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A standing wave has nodes and antinodes fixed in space; between consecutive nodes all points oscillate at the same frequency but with amplitudes that vary continuously with position, and they all move in phase (up together, down together). Options (A), (B), and (D) are correct.

The given displacement describes a standing wave on a string. Standing waves form when two identical traveling waves moving in opposite directions superpose. The key insight is that unlike a traveling wave where the disturbance propagates, in a standing wave each point oscillates in place with an amplitude that depends on its position.

The general form is y(x,t)=A(x)cos⁡(ωt+ϕ)y(x,t) = A(x) \cos(\omega t + \phi), where A(x)=0.06sin⁡(2πx/3)A(x) = 0.06\sin(2\pi x/3) is the position-dependent amplitude and ω=120π\omega = 120\pi rad/s governs the time variation.

Nodes occur where A(x)=0A(x) = 0, i.e., where sin⁡(2πx/3)=0\sin(2\pi x/3) = 0, giving x=0,32,3,92,…x = 0, \frac{3}{2}, 3, \frac{9}{2}, \ldots Between any two consecutive nodes, the sine function is either entirely positive or entirely negative, which determines the behavior of all points in that segment.

Let me examine each option for points between consecutive nodes:

1. Frequency (Option A)

Every point on the string oscillates with the time dependence cos⁡(120πt)\cos(120\pi t). The angular frequency is ω=120π\omega = 120\pi rad/s, corresponding to a frequency:

f=ω2π=120π2π=60 Hzf = \frac{\omega}{2\pi} = \frac{120\pi}{2\pi} = 60 \text{ Hz}

This is independent of position xx. All points, whether near a node or an antinode, complete 60 oscillations per second.

Option (A) is correct.

2. Phase (Option B)

The displacement at any point xx between two consecutive nodes is:

y(x,t)=0.06sin⁡(2πx/3)cos⁡(120πt)y(x,t) = 0.06\sin(2\pi x/3)\cos(120\pi t)

Between consecutive nodes, sin⁡(2πx/3)\sin(2\pi x/3) has a fixed sign (all positive or all negative). This means:

  • If sin⁡(2πx/3)>0\sin(2\pi x/3) > 0 in the segment, all points have displacement proportional to +cos⁡(120πt)+\cos(120\pi t)
  • If sin⁡(2πx/3)<0\sin(2\pi x/3) < 0 in the segment, all points have displacement proportional to −cos⁡(120πt)-\cos(120\pi t)

In either case, when cos⁡(120πt)=+1\cos(120\pi t) = +1, all points in that segment reach their maximum displacement simultaneously (in the same direction). When cos⁡(120πt)=0\cos(120\pi t) = 0, all points pass through equilibrium together. They move in phase with each other.

Note

Points on opposite sides of a node oscillate 180°180° out of phase (one segment moves up while the other moves down), but within a single segment between consecutive nodes, all points are in phase.

Option (B) is correct.

3. Energy (Option C) …

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