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Exercise 3.2 · Q4

Q.If A=[12−35021−11]A = \begin{bmatrix} 1 & 2 & -3 \\ 5 & 0 & 2 \\ 1 & -1 & 1 \end{bmatrix}, B=[3−12425203]B = \begin{bmatrix} 3 & -1 & 2 \\ 4 & 2 & 5 \\ 2 & 0 & 3 \end{bmatrix} and C=[4120321−23]C = \begin{bmatrix} 4 & 1 & 2 \\ 0 & 3 & 2 \\ 1 & -2 & 3 \end{bmatrix}, then compute (A+B)(A+B) and (B−C)(B-C). Also, verify that A+(B−C)=(A+B)−CA+(B-C) = (A+B)-C.

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Matrix addition is element-wise — you add or subtract corresponding entries. The associative property holds: A+(B−C)=(A+B)−CA+(B-C) = (A+B)-C. For the given matrices, the computed results confirm this identity.

Matrix addition (and subtraction) works exactly like adding or subtracting numbers, but applied to each corresponding position. If two matrices have the same dimensions, you simply combine the entries that sit in the same row and column. This is why the operation is called element-wise.

The property we're verifying — A+(B−C)=(A+B)−CA+(B-C) = (A+B)-C — is the associative law for addition and subtraction. It says that grouping doesn't matter: subtracting CC from BB first, then adding AA, gives the same result as adding AA and BB first, then subtracting CC. This works because matrix addition is commutative and associative, just like ordinary addition.

Let's compute step by step.


  1. Compute A+BA+B Add each corresponding entry:

A+B=[1+32+(−1)−3+25+40+22+51+2−1+01+3]=[41−19273−14]A+B = \begin{bmatrix} 1+3 & 2+(-1) & -3+2 \\ 5+4 & 0+2 & 2+5 \\ 1+2 & -1+0 & 1+3 \end{bmatrix} = \begin{bmatrix} 4 & 1 & -1 \\ 9 & 2 & 7 \\ 3 & -1 & 4 \end{bmatrix}

  1. Compute B−CB-C Subtract each entry of CC from the corresponding entry of BB:

B−C=[3−4−1−12−24−02−35−22−10−(−2)3−3]=[−1−204−13120]B-C = \begin{bmatrix} 3-4 & -1-1 & 2-2 \\ 4-0 & 2-3 & 5-2 \\ 2-1 & 0-(-2) & 3-3 \end{bmatrix} = \begin{bmatrix} -1 & -2 & 0 \\ 4 & -1 & 3 \\ 1 & 2 & 0 \end{bmatrix}

  1. Compute A+(B−C)A + (B-C) Add AA to the result from step 2:

A+(B−C)=[1+(−1)2+(−2)−3+05+40+(−1)2+31+1−1+21+0]=[00−39−15211]A + (B-C) = \begin{bmatrix} 1+(-1) & 2+(-2) & -3+0 \\ 5+4 & 0+(-1) & 2+3 \\ 1+1 & -1+2 & 1+0 \end{bmatrix} = \begin{bmatrix} 0 & 0 & -3 \\ 9 & -1 & 5 \\ 2 & 1 & 1 \end{bmatrix}

  1. Compute (A+B)−C(A+B)-C Subtract CC from the result of step 1: …

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