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Q.State Ampere's law. Apply it to determine the magnetic field at a point near an infinitely long straight wire carrying a current. (2+5=7)

Odisha ChseOdisha CHSE +2 Science Board Exam 2018Subjective· 7mImportance★★★★★
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Ampere's law (closed integral of B.dl = mu0 I_enc) on a circular loop of radius r around a straight wire gives B = mu0 I/(2 pi r).

Statement of Ampere's circuital law: The line integral of the magnetic field B⃗\vec B around any closed loop equals μ0\mu_0 times the total steady current II passing through the loop:

∮B⃗⋅dl⃗=μ0Ienclosed\oint \vec B \cdot d\vec l = \mu_0 I_{enclosed}

Application to a long straight current-carrying wire:

Step 1 — Choose the Amperian loop by symmetry. Around a long straight wire the field lines are concentric circles centred on the wire, and BB has the same magnitude everywhere on a circle of radius rr, directed tangentially. So take a circular loop of radius rr coaxial with the wire.

Step 2 — Evaluate the line integral. Since B⃗\vec B is parallel to dl⃗d\vec l everywhere on the circle and constant in magnitude:

∮B⃗⋅dl⃗=B∮dl=B (2πr)\oint \vec B\cdot d\vec l = B\oint dl = B\,(2\pi r).

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