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Q.With the help of a ray diagram, derive an expression for the magnifying power of a compound microscope. (2+3)

Odisha ChseOdisha CHSE +2 Science Board Exam 2026Subjective· 5mImportance★★★★★
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Figure — Stem 'With the help of a ray diagram, derive ... magnifying power of a compound microscope' is a necessity gat
Figure — Stem 'With the help of a ray diagram, derive ... magnifying power of a compound microscope' is a necessity gat

A compound microscope's total magnification is the product of the objective's linear magnification and the eyepiece's angular magnification, giving M≈(L/fo)(D/fe)M \approx (L/f_o)(D/f_e).

Ray diagram (described in words): The object ABAB is placed just beyond the focus FoF_o of the objective lens (a short-focal-length convex lens), which forms a real, inverted, magnified image A′B′A'B' inside the tube. This image A′B′A'B' acts as the object for the eyepiece (a second convex lens), and is positioned just inside the eyepiece's focal length FeF_e, so the eyepiece forms a large virtual, further magnified image A′′B′′A''B'', typically taken at the near point (distance DD) for maximum visual magnification. The final image is inverted with respect to the object and highly magnified.

Derivation of magnifying power: The overall magnifying power is the product of the linear magnification produced by the objective and the angular magnification produced by the eyepiece:

M=mo×meM = m_o \times m_e

The objective's linear magnification (real image) is

mo=vouom_o = \dfrac{v_o}{u_o}

where vov_o, uou_o are the image and object distances for the objective.

The eyepiece acts as a simple magnifier for the intermediate image; when the final image is formed at the near point DD, its angular magnification is

me=1+Dfem_e = 1+\dfrac{D}{f_e}

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