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Exercise 1.5 · Q1

Q.Let the population of the world in tt years after 2010 be given by the formula P=4.7(1.02)tP = 4.7(1.02)^{t} billions. Calculate the total population of the world in the year 2029 to the nearest million.

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✓ Free question

Convert the year 2029 to t=19t=19 years after 2010, substitute into the exponential growth formula, and round the resulting population to the nearest million.

[!FORMULA]

P=4.7(1.02)tP=4.7(1.02)^{t} billions, where tt = number of years after 2010.

  1. Find tt for the year 2029: t=2029−2010=19t=2029-2010=19.
  2. Compute (1.02)19(1.02)^{19} by successive squaring/multiplication: (1.02)10≈1.218994(1.02)^{10}\approx1.218994, (1.02)9≈1.195093(1.02)^{9}\approx1.195093, so (1.02)19=(1.02)10×(1.02)9≈1.218994×1.195093≈1.456811(1.02)^{19}=(1.02)^{10}\times(1.02)^{9}\approx1.218994\times1.195093\approx1.456811.
  3. Substitute into the formula: P=4.7×1.456811≈6.847012P=4.7\times1.456811\approx6.847012 billion.
  4. Convert to people: 6.8470126.847012 billion =6847.012=6847.012 million.
  5. Round to the nearest million: P≈6847P\approx6847 million =6,847,000,000=6{,}847{,}000{,}000 people.
✓Final answer

P=4.7(1.02)19≈6.847P=4.7(1.02)^{19}\approx6.847 billion ≈6,847,000,000\approx 6{,}847{,}000{,}000 people (nearest million).

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