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Exercise 1.5 · Q2

Q.Let the population of the world in tt years after 2010 be given by the formula P=4.7(1.02)tP = 4.7(1.02)^{t} billions. Find the year in which the population will be double of the population of 2020.

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Set P(t)=2P(10)P(t)=2P(10) (double the 2020 value) and solve the exponential equation for tt, then convert to a calendar year.

P(t)=4.7(1.02)tP(t) = 4.7(1.02)^{t} billions, where tt = number of years after 2010 and P(t)P(t) is the world population (tt years after 2010, in billions).

  1. Population in 2020 corresponds to t=2020−2010=10t = 2020-2010 = 10: P(10)=4.7(1.02)10P(10) = 4.7(1.02)^{10} billions.
  2. We want the year in which population is double this: P(t)=2P(10)P(t) = 2P(10), i.e. 4.7(1.02)t=2×4.7(1.02)104.7(1.02)^{t} = 2\times 4.7(1.02)^{10}.
  3. Cancel the common factor 4.74.7: (1.02)t=2(1.02)10(1.02)^{t} = 2(1.02)^{10}, so (1.02)t−10=2(1.02)^{t-10} = 2.
  4. Take natural logarithms on both sides: (t−10)log⁡(1.02)=log⁡2(t-10)\log(1.02) = \log 2. …

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