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Exercise 5.1 · Q13

Q.Find the middle terms of the A.P. 7,13,19,…,2477, 13, 19, \ldots, 247.

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The A.P. 7,13,19,…,2477,13,19,\ldots,247 has 4141 terms (odd), so it has exactly one middle term, the 2121st term, equal to 127127.

nnth term: an=a+(n−1)da_n=a+(n-1)d. If the total number of terms nn is odd, the unique middle term is the (n+12)\left(\dfrac{n+1}{2}\right)th term.

  1. Here a=7a=7, d=13−7=6d=13-7=6, last term l=247l=247.
  2. Number of terms: 247=7+(n−1)6⇒(n−1)=2406=40⇒n=41247=7+(n-1)6\Rightarrow (n-1)=\dfrac{240}{6}=40\Rightarrow n=41.
  3. Since n=41n=41 is odd, there is exactly one middle term, at position 41+12=21\dfrac{41+1}{2}=21. …

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