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Exercise 5.1 · Q18

Q.In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are 10 potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, and so on, until all potatoes are picked up and dropped in the bucket. Find the total distance run by the competitor.

Puducherry CbseNCERTSubjective· 3mImportance★★★★★est
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The one-way distances to the 10 potatoes form an A.P.; doubling their sum (there-and-back for each) gives a total distance of 370 m370\text{ m}.

Sum of nn terms of an A.P.: Sn=n2[2a+(n−1)d]S_n=\dfrac n2\big[2a+(n-1)d\big]. Total distance run =2×(sum of one-way distances)=2\times(\text{sum of one-way distances}), since each potato requires a round trip.

  1. Distance from the bucket to the 1st potato is 55 m; potatoes are 33 m apart, so the distance to the kkth potato is 5+(k−1)(3)5+(k-1)(3) m — an A.P. with a=5a=5, d=3d=3, n=10n=10 potatoes.
  2. One-way distances: 5,8,11,14,17,20,23,26,29,325,8,11,14,17,20,23,26,29,32 m.
  3. Sum of one-way distances: S10=102[2(5)+(10−1)(3)]=5[10+27]=5×37=185S_{10}=\dfrac{10}{2}\big[2(5)+(10-1)(3)\big]=5\big[10+27\big]=5\times37=185 m. …

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