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Exercise 5.4 · Q11

Q.Priyanka invested ₹1300 in an account that pays 4% interest compounded annually. Assuming no deposits or withdrawals are made, find how much money she would have in the account 6 years after her initial investment. (Adapted from DeltaMath)

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Apply the compound-interest formula to ₹1300\text{₹}1300 growing at 4%4\% per year for 66 years.

Compound amount: A=P(1+r)nA=P\left(1+r\right)^{n}, where P=P= principal, r=r= annual interest rate (as a decimal), n=n= number of years.

  1. Given: P=₹1300P=\text{₹}1300, annual rate =4%⇒r=0.04=4\%\Rightarrow r=0.04, n=6n=6 years.
  2. Substitute into the formula:

A=1300(1+0.04)6=1300(1.04)6A=1300(1+0.04)^6=1300(1.04)^6

  1. Compute (1.04)6(1.04)^6 stepwise: (1.04)2=1.0816(1.04)^2=1.0816; (1.04)3=1.0816×1.04=1.124864(1.04)^3=1.0816\times1.04=1.124864; (1.04)6=(1.124864)2≈1.265319(1.04)^6=\left(1.124864\right)^2\approx1.265319.
  2. Multiply by the principal: A=1300×1.265319≈1644.91A=1300\times1.265319\approx1644.91. …

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