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Exercise 5.4 · Q15

Q.A small country emits 130,100 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by 3.1% per year for the next 3 years. In the first year, as per a special agreement, the country will keep its emissions at 130,000 kilotons and the emissions will decrease 3.1% in each of the next two years. How many kilotons of carbon dioxide would the country emit over the course of the 3-year period? (Geometric Series — Deltamath.com)

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Starting from 130,000 kilotons in Year 1, emissions fall by 3.1%3.1\% each of the next two years — a decreasing GP; sum the three years.

Sum of the first nn terms of a GP: Sn=a(1−rn)1−rS_n=\dfrac{a(1-r^n)}{1-r} (for r<1r<1), where a=a= Year-1 emissions, r=r= common ratio =1−(decrease rate)=1-(\text{decrease rate}), n=n= number of years.

  1. Year-1 emissions (as agreed, held at): a=130,000a=130{,}000 kt.
  2. Each subsequent year decreases by 3.1%3.1\%, so common ratio r=1−0.031=0.969r=1-0.031=0.969.
  3. Number of years: n=3n=3.
  4. Compute each year's emissions:
    • Year 1: 130,000130{,}000 kt
    • Year 2: 130,000×0.969=125,970130{,}000\times0.969=125{,}970 kt
    • Year 3: 125,970×0.969=122,064.93125{,}970\times0.969=122{,}064.93 kt
  5. Sum all three years: S3=130,000+125,970+122,064.93S_3=130{,}000+125{,}970+122{,}064.93 …

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