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Exercise 5.1 · Q10

Q.x3>x2+1\dfrac{x}{3} > \dfrac{x}{2} + 1

Puducherry CbseNCERTSubjective· 2mImportance★★★★★
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The inequality x3>x2+1\frac{x}{3} > \frac{x}{2} + 1 simplifies to x<−6x < -6 after clearing denominators and isolating xx. The solution set is all real numbers less than −6-6.

Why This Approach Works

When you see an inequality with fractions, the natural instinct is to clear denominators — but you must be careful. Unlike equations, multiplying or dividing by a negative number flips the inequality sign. Here, the denominators are positive (3 and 2), so we can multiply through safely. The key is to isolate xx step by step, treating the inequality like a balance scale: whatever you do to one side, you do to the other.

Step-by-Step Solution

  1. Write the inequality clearly We have:

x3>x2+1\frac{x}{3} > \frac{x}{2} + 1

  1. Eliminate fractions by multiplying by the LCM The least common multiple of 3 and 2 is 6. Multiply both sides by 6. Since 6 is positive, the inequality direction stays the same:

6⋅x3>6⋅(x2+1)6 \cdot \frac{x}{3} > 6 \cdot \left( \frac{x}{2} + 1 \right)

Simplify:

2x>3x+62x > 3x + 6

Tip

Multiplying by the LCM is faster than combining fractions. Just remember: multiply every term on both sides, not just the fractions.

  1. Bring variable terms to one side Subtract 3x3x from both sides to collect xx terms on the left:

2x−3x>62x - 3x > 6

This gives:

−x>6-x > 6

  1. Isolate xx by dividing by −1-1 Dividing both sides by −1-1 flips the inequality sign: x<−6x < -6 …

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