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Exercise 5.1 · Q17

Q.3x−2<2x+13x - 2 < 2x + 1

Puducherry CbseNCERTSubjective· 2mImportance★★★★★
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The inequality 3x−2<2x+13x - 2 < 2x + 1 simplifies to x<3x < 3, meaning all real numbers less than 3 satisfy it. The solution set is (−∞,3)(-\infty, 3).

Why This Works

Linear inequalities work almost exactly like linear equations — you isolate the variable by performing the same operation on both sides. The only extra rule is that multiplying or dividing by a negative number flips the inequality sign. Here, no such flip is needed, so it's as straightforward as solving 3x−2=2x+13x - 2 = 2x + 1, but with a "<" instead of "=".

The goal is to get xx alone on one side. Every step preserves the truth of the inequality as long as we treat both sides equally.

Step-by-Step Solution

  1. Write the inequality clearly.

3x−2<2x+13x - 2 < 2x + 1

  1. Move the xx-terms to one side. Subtract 2x2x from both sides to keep the coefficient of xx positive (this avoids sign-flipping later).

3x−2−2x<2x+1−2x3x - 2 - 2x < 2x + 1 - 2x

Simplifying:

x−2<1x - 2 < 1

  1. Isolate xx by moving the constant. Add 22 to both sides:

x−2+2<1+2x - 2 + 2 < 1 + 2

Which gives:

x<3x < 3

  1. Interpret the result. The inequality x<3x < 3 means any real number strictly less than 3 works. In interval notation, this is (−∞,3)(-\infty, 3). On a number line, you'd draw an open circle at 3 and shade everything to the left. …

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