Q.A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If we have 640 litres of the 8% solution, how many litres of the 2% solution will have to be added?
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Start your 14-day free trial to unlock the full solution →We treat this as a mixture concentration problem: adding litres of 2% solution to 640 litres of 8% solution gives a final concentration between 4% and 6%. Solving the two inequalities yields litres.
Why mixture concentration works
When you combine two solutions of different strengths, the final concentration is a weighted average of the two — weighted by the volumes. If you add a weaker solution to a stronger one, the result lies somewhere in between. The exact position depends on how much of each you mix. This is the core idea: the total amount of boric acid divided by the total volume gives the new percentage.
Let the volume of 2% solution added be litres.
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Total boric acid after mixing
The 8% solution contributes litres of pure boric acid.
The 2% solution contributes litres.
So total boric acid = litres.
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Total volume after mixing
litres.
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Final concentration
This must lie strictly between 4% and 6%, i.e. between and .
- Set up the double inequality
- Solve the left inequality (mixture > 4%)
Multiply both sides by — which is positive, so inequality direction stays:
- Solve the right inequality (mixture < 6%)
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