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Exercise 9.1 · Q11

Q.A line passes through (x1,y1)(x_1, y_1) and (h,k)(h, k). If slope of the line is mm, show that k−y1=m(h−x1)k - y_1 = m(h - x_1).

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The slope formula m=ΔyΔxm = \frac{\Delta y}{\Delta x} directly gives k−y1=m(h−x1)k - y_1 = m(h - x_1) when rearranged — this is the point-slope form of a line.

Why This Works

The slope of a line is a measure of its steepness — how much the yy-coordinate changes for each unit change in xx. If you know two points on the line, the slope is simply the ratio of the vertical change to the horizontal change. That's the core idea here.

When we say a line passes through (x1,y1)(x_1, y_1) and (h,k)(h, k) with slope mm, we are essentially saying: the ratio of the difference in yy to the difference in xx between these two points equals mm. The equation k−y1=m(h−x1)k - y_1 = m(h - x_1) is just that statement, rearranged.


Step-by-Step Derivation

  1. Recall the definition of slope. For any two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) on a non-vertical line, the slope mm is given by:

m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

This is the rise (change in yy) divided by the run (change in xx).

  1. Identify the two points in the problem. Here, the two points are (x1,y1)(x_1, y_1) and (h,k)(h, k). So we set:

x2=h,y2=kx_2 = h, \quad y_2 = k

  1. Substitute into the slope formula. Plugging these into the definition:

m=k−y1h−x1m = \frac{k - y_1}{h - x_1}

Watch out

A common mistake is to swap the order — e.g., writing y1−kx1−h\frac{y_1 - k}{x_1 - h}. That gives the same numerical value (since both numerator and denominator flip sign), but it's safer to keep the order consistent: second point minus first point.

  1. Multiply both sides by (h−x1)(h - x_1). To isolate the relationship between kk, y1y_1, hh, and x1x_1, multiply through:

m(h−x1)=k−y1m(h - x_1) = k - y_1

  1. Rewrite in the required form. …

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