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Exercise 9.1 · Q7

Q.Find the slope of the line, which makes an angle of 30∘30^\circ with the positive direction of y-axis measured anticlockwise.

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Slope is tan⁡θ\tan\theta, where θ\theta is the angle the line makes with the positive x-axis, measured anticlockwise. Here the line makes 30∘30^\circ with the positive y-axis, measured anticlockwise -- since the positive y-axis is already 90∘90^\circ from the positive x-axis, rotating a further 30∘30^\circ anticlockwise puts the line at 90∘+30∘=120∘90^\circ + 30^\circ = 120^\circ from the x-axis. So the slope is tan⁡120∘=−3\tan 120^\circ = -\sqrt{3}.

The key idea: slope is always defined relative to the x-axis. When a problem gives an angle with the y-axis, you must convert it to the angle with the x-axis before taking the tangent -- and the direction of measurement (clockwise vs anticlockwise) decides which way that conversion goes.


Why this works

The slope mm of a non-vertical line is defined as m=tan⁡θm = \tan \theta, where θ\theta is the angle the line makes with the positive direction of the x-axis, measured anticlockwise, 0∘≤θ≤180∘0^\circ \le \theta \le 180^\circ. This is the standard convention used throughout this chapter.

The positive x-axis and positive y-axis are 90∘90^\circ apart (the y-axis lies 90∘90^\circ anticlockwise from the x-axis). So if a line's angle with the y-axis is known, its angle with the x-axis can be found by adding or subtracting 90∘90^\circ -- which operation applies depends on which direction the given angle is measured.

Step-by-step solution

  1. Understand the given angle.

    The line makes an angle of 30∘30^\circ with the positive direction of the y-axis, measured anticlockwise. "Measured anticlockwise" means: starting from the positive y-axis, rotate anticlockwise by 30∘30^\circ to reach the line.

  2. Find the angle with the x-axis.

    The positive y-axis itself is 90∘90^\circ anticlockwise from the positive x-axis. Rotating a further 30∘30^\circ anticlockwise from the y-axis carries the line past the y-axis into the second quadrant, so its angle with the positive x-axis is …

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