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Worked Examples · Example 18

Q.Find the minor of element −11-11 in A=∣6−11−13∣A = \begin{vmatrix} 6 & -11 \\ -1 & 3 \end{vmatrix}.

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✓ Free question

The minor of an element is the determinant left after deleting that element's row and column; deleting row 1 and column 2 of the 2×22\times2 array leaves the single number −1-1.

Mij=determinant obtained by deleting the i-th row and j-th column.M_{ij} = \text{determinant obtained by deleting the } i\text{-th row and } j\text{-th column.}

Here A=∣6−11−13∣A = \begin{vmatrix} 6 & -11 \\ -1 & 3 \end{vmatrix} and −11=a12-11 = a_{12} (row 1, column 2).

  1. Locate the element −11-11: it lies in row 1, column 2, so we need the minor M12M_{12}.
  2. Delete row 1 and column 2 from ∣6−11−13∣\begin{vmatrix} 6 & -11 \\ -1 & 3 \end{vmatrix}.
  3. The only remaining entry is the one in row 2, column 1, namely −1-1.
  4. Therefore the minor M12=−1M_{12} = -1.
✓Final answer

The minor of the element −11-11 is M12=−1M_{12} = -1.

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