Minor of a Matrix Element – From Intuition to Precision
Imagine you have a large matrix — say a 3×3 grid of numbers. You pick one specific element, like the number in the second row and third column. Now ask: if I wanted to ignore that element and everything in its row and column, what smaller matrix remains? That smaller matrix is the key.
The minor of an element is simply the determinant of that leftover submatrix. It captures the "influence" of that element when you strip away its entire row and column.
The Intuition First
Think of a matrix as a system of equations. Each row is an equation, each column a variable. When you focus on one element, you are asking: what happens to the rest of the system if I remove the equation and the variable that this element belongs to? The minor tells you the "size" (determinant) of that reduced system.
For a 2×2 matrix, the minor of any element is just the single number diagonally opposite it — because removing one row and one column leaves a 1×1 matrix, whose determinant is that number itself.
For a 3×3 matrix, the minor of an element is the determinant of a 2×2 matrix formed by the four numbers that are not in the same row or column as the chosen element.
The Precise Statement
Let A be an n×n square matrix. Let aij be the element in the i-th row and j-th column.
Mij=det(matrix obtained by deleting row i and column j from A)
Mij is called the minor of the element aij.
A Concrete Example
Take the matrix:
A=123456789
Find the minor of the element a23=8 (row 2, column 3).
Delete row 2 and column 3. What remains?
(1346)
The minor is the determinant of this 2×2 matrix:
M23=(1)(6)−(4)(3)=6−12=−6
So the minor of 8 is −6.
Tip
The minor is not the element itself — it is the determinant of the submatrix left after removing that element's row and column. For a 1×1 matrix, the minor of the single element is 1 (the determinant of an empty matrix is defined as 1), but that's a special case.
Why Minors Matter
Minors are the building blocks of cofactors, which in turn are used to compute determinants of large matrices (Laplace expansion) and to find inverses. Every time you expand a determinant along a row or column, you are summing products of elements and their minors (with appropriate signs).
Important
The minor Mij is always a number (a scalar), not a matrix. It is the determinant of a smaller square matrix.
A Common Mistake to Avoid
Students often confuse the minor with the element itself or with the submatrix. The submatrix is the 2×2 block of numbers; the minor is the determinant of that block. They are not the same thing.
Watch out
For a 3×3 matrix, the minor of an element is not the element diagonally opposite it. That is only true for 2×2 matrices. For 3×3, you must compute the 2×2 determinant.
Quick Check
For the same matrix A above, find M12 (minor of a12=4).
Delete row 1 and column 2:
(2389)
M12=(2)(9)−(8)(3)=18−24=−6
Notice that M12=M23 in this particular matrix — that is a coincidence, not a rule.
Final takeaway: The minor of an element is the determinant of the matrix you get by crossing out that element's row and column. It is a single number that measures the "weight" of that element in the larger matrix's structure.
Applying the column operation C3→C3+C2 turns the third column into a multiple of the first column, so two columns become proportional and the determinant is forced to zero.
✓Final answer
Δ=0.
Applying the column operation C3→C3+C2 makes column 3 equal to (a+b+c) times column 1, so two columns become proportional and Δ=0.
Column operation Ci→Ci+Cj leaves Δ unchanged; if two columns are proportional, Δ=0.
Start with Δ=111abcb+ca+ca+b.
Apply C3→C3+C2 (add column 2 to column 3):
Δ=111abca+b+ca+b+ca+b+c.
Take the common factor (a+b+c) out of column 3:
Δ=(a+b+c)111abc111.
Column 1 and column 3 are identical, so the determinant of the 3×3 array is 0.