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Worked Examples · Example 8

Q.If X=[−1384]X = \begin{bmatrix} -1 & 3 \\ 8 & 4 \end{bmatrix} and Y=[−51−1−2]Y = \begin{bmatrix} -5 & 1 \\ -1 & -2 \end{bmatrix} then find the matrix ZZ, such that 2X+Y=5Z2X+Y = 5Z.

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Compute 2X+Y2X+Y, then divide every entry by 5 to isolate ZZ from 2X+Y=5Z2X+Y=5Z.

From 2X+Y=5Z2X+Y=5Z we get Z=15 (2X+Y)Z=\dfrac{1}{5}\,(2X+Y), where scalar multiplication and matrix addition act entry-by-entry.

  1. Compute 2X2X:

2X=[−26168].2X=\begin{bmatrix} -2 & 6 \\ 16 & 8 \end{bmatrix}.

  1. Add YY:

2X+Y=[−2+(−5)6+116+(−1)8+(−2)]=[−77156].2X+Y=\begin{bmatrix} -2+(-5) & 6+1 \\ 16+(-1) & 8+(-2) \end{bmatrix}=\begin{bmatrix} -7 & 7 \\ 15 & 6 \end{bmatrix}.

  1. Divide by 5: …

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