Skip to content
Worked Examples · Example 39

Q.Let the cost function of firm be given by the equation C(x)=300x−10x2+13x3C(x) = 300x - 10x^2 + \dfrac{1}{3}x^3. Find the output at which the marginal cost MC is minimum.

Puducherry CbseNCERTSubjective· 3mImportance★★★★★
45% · 39/87 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

MC=C′(x)=x2−20x+300;MC=C'(x)=x^2-20x+300; its minimum is at x=10,x=10, where MC=200.MC=200.

Marginal cost MC=dCdx=C′(x).MC=\dfrac{dC}{dx}=C'(x). To minimise MC,MC, set d(MC)dx=0\dfrac{d(MC)}{dx}=0 and check the second derivative >0.>0.

  1. Given cost function: C(x)=300x−10x2+13x3.C(x)=300x-10x^2+\dfrac{1}{3}x^3.
  2. Marginal cost: MC=C′(x)=300−20x+x2=x2−20x+300.MC=C'(x)=300-20x+x^2=x^2-20x+300.
  3. Differentiate MCMC: d(MC)dx=2x−20.\dfrac{d(MC)}{dx}=2x-20.
  4. Critical point: 2x−20=0⇒x=10.2x-20=0\Rightarrow x=10. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.