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Worked Examples · Example 40

Q.A pen drive manufacturing company charges ₹6,000 per unit for an order of 50 pen drives or less. The charge is reduced by ₹75 per pen drive for each order in excess of 50. Find the largest size order, the company should allow so as to receive maximum revenue.

Puducherry CbseNCERTSubjective· 5mImportance★★★★★
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Let xx be the number of units in excess of 50.50. Revenue R=(50+x)(6000−75x)R=(50+x)(6000-75x) is maximised at x=15,x=15, i.e. an order of 6565 pen drives.

Revenue == (number of units) ×\times (price per unit). Maximise R(x)R(x) with R′(x)=0,R'(x)=0, R′′(x)<0.R''(x)<0.

  1. Set the variable: let x=x= number of pen drives ordered in excess of 50,50, so total order =50+x.=50+x.
  2. Price per unit: reduced by ₹75₹75 for each unit above 50,50, so price =6000−75x=6000-75x (₹).
  3. Revenue function: R=(50+x)(6000−75x)=300000−3750x+6000x−75x2=300000+2250x−75x2.R=(50+x)(6000-75x)=300000-3750x+6000x-75x^2=300000+2250x-75x^2.
  4. Differentiate: R′(x)=2250−150x.R'(x)=2250-150x.
  5. Critical point: R′(x)=0⇒2250=150x⇒x=15.R'(x)=0\Rightarrow 2250=150x\Rightarrow x=15.
  6. Confirm maximum: R′′(x)=−150<0,R''(x)=-150<0, so revenue is maximum at x=15.x=15. …

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