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Mathematics · Ch 5 — Continuity and Differentiability

Derivatives of Functions in Parametric Forms

5.6

Derivatives of Functions in Parametric Forms

Parametric Relations: A New Way to Connect Variables

Sometimes the relationship between xx and yy is given neither explicitly as y=f(x)y = f(x) nor implicitly as F(x,y)=0F(x, y) = 0. Instead, both xx and yy are expressed separately in terms of a third variable — the parameter — which links them through their individual dependence on it.

Writing x=f(t)x = f(t) and y=g(t)y = g(t) expresses the relation between xx and yy in parametric form, with tt as the parameter. For example, the circle x2+y2=a2x^2 + y^2 = a^2 can be written parametrically as x=acos⁡θx = a\cos\theta, y=asin⁡θy = a\sin\theta, where θ\theta is the parameter.

Finding dydx\frac{dy}{dx} in Parametric Form

Since both xx and yy are functions of tt, the chain rule gives

dydt=dydx⋅dxdt\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}

Rearranging yields the fundamental formula:

Derivative in Parametric Form

dydx=dydtdxdt,provided dxdt≠0\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}, \quad \text{provided } \frac{dx}{dt} \neq 0

In terms of the functions x=f(t)x = f(t) and y=g(t)y = g(t), this becomes

dydx=g′(t)f′(t),provided f′(t)≠0\frac{dy}{dx} = \frac{g'(t)}{f'(t)}, \quad \text{provided } f'(t) \neq 0

Watch out

A common mistake is to forget the condition dxdt≠0\frac{dx}{dt} \neq 0 (or f′(t)≠0f'(t) \neq 0). If the denominator is zero, dydx\frac{dy}{dx} is undefined at that point and the chain-rule derivation breaks down. …