5.5 Logarithmic Differentiation
Why Logarithmic Differentiation?
The standard rules handle xn (variable base, constant exponent) and ax (constant base, variable exponent). But for [u(x)]v(x), where both base and exponent are functions of x, neither the power rule nor the exponential rule applies directly. Logarithmic differentiation is the systematic method: take the natural log of both sides of y=f(x), simplify with logarithm properties, then differentiate implicitly.
Prerequisite: f(x) and the base u(x) must be strictly positive for all x considered, or their logarithms are undefined in the real number system.
The General Method
Let y=f(x)=[u(x)]v(x), with u(x)>0 and v(x) differentiable.
Step 1 — take natural logarithm (base e) on both sides:
logy=log([u(x)]v(x))
Step 2 — apply the power rule log(ab)=bloga:
logy=v(x)⋅log[u(x)]
Step 3 — differentiate both sides w.r.t. x (chain rule on the left, product rule on the right):
dxd(logy)=y1⋅dxdy
dxd[v(x)⋅log[u(x)]]=v′(x)⋅log[u(x)]+v(x)⋅u(x)u′(x)
using dxd(log[u(x)])=u(x)u′(x) by the chain rule.
Step 4 — equate and multiply both sides by y:
y1⋅dxdy=v′(x)⋅log[u(x)]+u(x)v(x)⋅u′(x)
dxdy=y[v′(x)⋅log[u(x)]+u(x)v(x)⋅u′(x)]
Step 5 — substitute back y=[u(x)]v(x):
dxdy=[u(x)]v(x)[v′(x)⋅log[u(x)]+u(x)v(x)⋅u′(x)]
Logarithmic Differentiation Formula
dxd([u(x)]v(x))=[u(x)]v(x)[v′(x)log[u(x)]+u(x)v(x)u′(x)]
Special Case: Differentiating ax (Constant Base)
This is the general formula with u(x)=a (constant, a>0) and v(x)=x.
Method 1 (logarithmic differentiation): Let y=ax. Then logy=xloga, so …