Q.In an unbiased p-n junction, holes diffuse from the p-region to n-region because
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Start your 14-day free trial to unlock the full solution →Holes diffuse from p to n due to a concentration gradient — there are far more holes in the p-region than in the n-region. The correct option is (c).
Why this question matters — and the common trap
This is a classic Class 12 Physics question on semiconductor diodes. The key is to separate diffusion (driven by concentration difference) from drift (driven by electric field). Many students mix these up, especially when they hear "potential difference" or "attraction" — those belong to the drift mechanism, not the initial diffusion.
Let’s build the picture from scratch.
Formation of an unbiased p-n junction
When a p-type semiconductor (excess holes) and an n-type semiconductor (excess electrons) are joined, there is no battery or external voltage — it is unbiased. At the instant of joining:
- The p-side has a very high concentration of holes ().
- The n-side has a very low concentration of holes (only thermally generated, ).
Nature abhors a steep gradient. Particles always move from a region of higher concentration to a region of lower concentration — this is diffusion. So holes rush from p to n, and electrons rush from n to p.
Do not think that holes are "attracted" by electrons in the n-region. That would imply an electric force, which only arises after diffusion creates a space-charge region. The initial motion is purely due to concentration difference — no electric field exists yet.
Step-by-step reasoning
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Identify the driving force for diffusion
Diffusion is a statistical process. In the p-region, holes are densely packed; in the n-region, they are scarce. Random thermal motion causes more holes to cross from the high-density side to the low-density side than the reverse. The net movement is from p to n.
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Why option (a) is wrong
"Free electrons in the n-region attract them" — this describes an electrostatic attraction. But in an unbiased junction, before any charge movement, there is no electric field. Attraction would require opposite charges to already be separated, which hasn't happened yet. After diffusion begins, the exposed immobile ions do create a field, but that field opposes further diffusion (it's the built-in potential). So attraction is not the cause; it's a consequence that eventually stops diffusion.
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Why option (b) is wrong …
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