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Exercises · Q19

Q.Using the principle of mathematical induction, prove that 7n−3n7^{n} - 3^{n} is divisible by 44 for every natural number nn.

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Basis step (n=1n=1): 71−31=7−3=47^1-3^1 = 7-3=4, which is divisible by 44. So P(1)P(1) is true.

Inductive step: assume P(k)P(k) is true, i.e. 7k−3k=4m7^k-3^k = 4m for some integer mm.

Consider 7k+1−3k+17^{k+1}-3^{k+1}. Rewrite it so that 7k−3k7^k-3^k appears explicitly, by adding and subtracting 7⋅3k7\cdot3^k:

7k+1−3k+1=7⋅7k−3⋅3k=7⋅7k−7⋅3k+7⋅3k−3⋅3k=7(7k−3k)+3k(7−3)7^{k+1}-3^{k+1} = 7\cdot7^k - 3\cdot3^k = 7\cdot7^k - 7\cdot3^k + 7\cdot3^k - 3\cdot3^k = 7(7^k-3^k) + 3^k(7-3)

=7(7k−3k)+4⋅3k=7(4m)+4⋅3k=4(7m+3k)= 7(7^k-3^k) + 4\cdot3^k = 7(4m) + 4\cdot3^k = 4(7m+3^k)

Since 7m+3k7m+3^k is an integer, 7k+1−3k+17^{k+1}-3^{k+1} is a multiple of 44, so P(k+1)P(k+1) is true whenever P(k)P(k) is.

By induction, 7n−3n7^n-3^n is divisible by 44 for every natural number nn. …

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