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Worked Examples · Example 2

Q.Two salespersons, A and B, recorded the following daily sales (in ₹'000) over 5 days.
A: 20, 22, 24, 26, 28
B: 15, 20, 25, 30, 35
Find the coefficient of variation for each, and state which salesperson has more consistent sales.

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✓ Free question

Salesperson A: 20, 22, 24, 26, 28.

Mean: xˉA=20+22+24+26+285=1205=24\bar x_A = \dfrac{20+22+24+26+28}{5} = \dfrac{120}{5}=24.

Deviations from mean: −4,−2,0,2,4-4,-2,0,2,4. Squared: 16,4,0,4,1616,4,0,4,16. Sum =40=40.

σA=40/5=8≈2.83\sigma_A = \sqrt{40/5} = \sqrt{8} \approx 2.83.

CVA=2.8324×100≈11.79%CV_A = \dfrac{2.83}{24}\times100 \approx 11.79\%.

Salesperson B: 15, 20, 25, 30, 35.

Mean: xˉB=15+20+25+30+355=1255=25\bar x_B = \dfrac{15+20+25+30+35}{5} = \dfrac{125}{5}=25.

Deviations from mean: −10,−5,0,5,10-10,-5,0,5,10. Squared: 100,25,0,25,100100,25,0,25,100. Sum =250=250.

σB=250/5=50≈7.07\sigma_B = \sqrt{250/5} = \sqrt{50} \approx 7.07.

CVB=7.0725×100≈28.28%CV_B = \dfrac{7.07}{25}\times100 \approx 28.28\%.

Comparison. CVA (≈11.79%)<CVB (≈28.28%)CV_A\,(\approx11.79\%) < CV_B\,(\approx28.28\%), so Salesperson A's sales are more consistent (less variable relative to their own average), even though B's average sales are slightly higher.

Independent check. A's raw spread (28−20=8) is much tighter around a similar-sized mean than B's raw spread (35−15=20) — the range comparison alone already points toward A being more consistent, matching the CV-based conclusion reached through the full calculation.

✓Final answer

CVA≈11.79%CV_A \approx 11.79\%; CVB≈28.28%CV_B \approx 28.28\%. Since a lower CV means greater consistency, Salesperson A has more consistent sales.

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