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Exercises · Q10

Q.Find the present value of an ordinary annuity of ₹6,000 paid at the end of every year for 3 years at 9% per annum compound interest. [Given (1.09)−3=0.7722(1.09)^{-3} = 0.7722]

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Step 1 — Identify the values. P=6000P=6000, i=0.09i=0.09, n=3n=3.

Step 2 — Apply the formula.

V=6000[1−(1.09)−30.09]=6000[1−0.77220.09]=6000[0.22780.09]V = 6000\left[\dfrac{1-(1.09)^{-3}}{0.09}\right] = 6000\left[\dfrac{1-0.7722}{0.09}\right] = 6000\left[\dfrac{0.2278}{0.09}\right]

Step 3 — Compute. 0.22780.09≈2.5311\dfrac{0.2278}{0.09} \approx 2.5311. V≈6000×2.5311≈15,187V \approx 6000\times2.5311 \approx 15{,}187. …

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