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Worked Examples · Example 2

Q.A person wants to receive ₹8,000 at the end of every year for 3 years. Find the amount they must invest today at 8% per annum compound interest to achieve this. [Given (1.08)−3=0.7938(1.08)^{-3} = 0.7938]

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✓ Free question

Step 1 — Identify the values. P=8000P=8000, i=0.08i=0.08, n=3n=3.

Step 2 — Apply the present value formula.

V=P[1−(1+i)−ni]=8000[1−(1.08)−30.08]V = P\left[\dfrac{1-(1+i)^{-n}}{i}\right] = 8000\left[\dfrac{1-(1.08)^{-3}}{0.08}\right]

Step 3 — Substitute (1.08)−3=0.7938(1.08)^{-3}=0.7938.

V=8000[1−0.79380.08]=8000[0.20620.08]=8000(2.5775)=20,620V = 8000\left[\dfrac{1-0.7938}{0.08}\right] = 8000\left[\dfrac{0.2062}{0.08}\right] = 8000(2.5775) = 20{,}620

Independent check (discount each payment separately). The payment at the end of year 1, discounted back 1 year: 8000(1.08)−1=8000/1.08≈7407.48000(1.08)^{-1} = 8000/1.08 \approx 7407.4. Year 2's payment, discounted back 2 years: 8000(1.08)−2≈8000/1.1664≈6858.78000(1.08)^{-2} \approx 8000/1.1664 \approx 6858.7. Year 3's payment, discounted back 3 years: 8000(0.7938)=6350.48000(0.7938) = 6350.4. Total: 7407.4+6858.7+6350.4≈20,616.57407.4+6858.7+6350.4 \approx 20{,}616.5 — matching the formula's 20,62020{,}620 closely (the small gap is rounding in the intermediate discount factors, not an error).

✓Final answer

The person must invest approximately ₹20,620 today to receive ₹8,000 at the end of each of the next 3 years.

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