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Choose the Best Answer · Q7

Q.1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas. The percentage of impurity in the sample is

(a) 0%
(b) 4.4%
(c) 16%
(d) 8.4%
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Step 1. Reaction: MgCO3 →(Δ) MgO + CO2. Molar mass MgCO3 = 24+12+48 = 84 g mol^-1; molar mass CO2 = 44 g mol^-1.

Step 2. Mass of pure MgCO3 that would give 0.44 g CO2 = (84/44) × 0.44 = 0.84 g. …

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